Back to Minimum overlap problem

n = 49
f(x) = 0 for 0x < 8/49
f(x) = 0.00647468352772for 8/49x < 10/49
f(x) = 0.21647681825379for 10/49x < 12/49
f(x) = 0.59077752917036for 12/49x < 14/49
f(x) = 0.16355762786237for 14/49x < 16/49
f(x) = 0.82845576206124for 16/49x < 18/49
f(x) = 1for 18/49x < 20/49
f(x) = 0.21180974556365for 20/49x < 22/49
f(x) = 0.07710650229582for 22/49x < 24/49
f(x) = 0.34204906397597for 24/49x < 26/49
f(x) = 0.72477988844473for 26/49x < 28/49
f(x) = 0.88810141495243for 28/49x < 30/49
f(x) = 0.67254960734442for 30/49x < 32/49
f(x) = 0.43482515558899for 32/49x < 34/49
f(x) = 0.68160979113197for 34/49x < 36/49
f(x) = 0.58794531007594for 36/49x < 38/49
f(x) = 0.71662625338243for 38/49x < 40/49
f(x) = 0.78808131960861for 40/49x < 42/49
f(x) = 1for 42/49x < 44/49
f(x) = 0.93948581030243for 44/49x < 46/49
f(x) = 0.97295024833531for 46/49x < 48/49
f(x) = 0.81267493624364for 48/49x ≤ 1
f(x) = f(2-x)for 1< x ≤ 2
Illustration
α(f) < 0.38096406669462
 maximal for 4/49 ≤ |k| ≤ 40/49

Discovered: May 2011