Back to Minimum overlap problem

n = 29
f(x) = 0 for 0x < 6/29
f(x) = 0.2676058656518283for 6/29x < 8/29
f(x) = 0.9929440254233889for 8/29x < 10/29
f(x) = 0.0570326141757860for 10/29x < 12/29
f(x) = 0.5121827619825924for 12/29x < 14/29
f(x) = 0.6142279296508323for 14/29x < 16/29
f(x) = 0.6313715832167212for 16/29x < 18/29
f(x) = 0.4478634372721209for 18/29x < 20/29
f(x) = 0.7700613804387751for 20/29x < 22/29
f(x) = 0.7534956165417719for 22/29x < 24/29
f(x) = 0.8178911132455888for 24/29x < 26/29
f(x) = 0.8987824211599151for 26/29x < 28/29
f(x) = 0.9730825024813582for 28/29x ≤ 1
f(x) = f(2-x)for 1< x ≤ 2
Illustration
α(f) < 0.38098987465276
 maximal for 2/29 ≤ |k| ≤ 24/29
Discovered: April 2011