Back to Minimum overlap problem
n
= 5
for 0
≤
x
< 2/5
for 2/5
≤
x
< 4/5
for 4/5
≤
x
≤ 1
f
(
x
) =
f
(2-
x
)
for 1
<
x
≤ 2
Illustration
maximal for 2/5 ≤ |
k
| ≤ 4/5