Back to Minimum overlap problem

n = 51
f(x) = 0 for 0x < 10/51
f(x) = 0.0002938681556273for 10/51x < 12/51
f(x) = 0.5952882223921177for 12/51x < 14/51
f(x) = 0.7844530825484313for 14/51x < 16/51
f(x) = 0.8950034338013842for 16/51x < 18/51
f(x) = 0.0597964076006748for 18/51x < 20/51
f(x) = 0.0189602838469592for 20/51x < 22/51
f(x) = 0.7420501628172980for 22/51x < 24/51
f(x) = 0.6444559588500921for 24/51x < 26/51
f(x) = 0.3549040817844764for 26/51x < 28/51
f(x) = 0.8762442385073478for 28/51x < 30/51
f(x) = 0.5437907313675501for 30/51x < 32/51
f(x) = 0.2679640048997296for 32/51x < 34/51
f(x) = 0.8518954615823791for 34/51x < 36/51
f(x) = 0.5211171156914872for 36/51x < 38/51
f(x) = 1for 38/51x < 40/51
f(x) = 0.5506146790047043for 40/51x < 42/51
f(x) = 0.9007715390796991for 42/51x < 44/51
f(x) = 0.8229000691941086for 44/51x < 46/51
f(x) = 0.8879541710440111for 46/51x < 48/51
f(x) = 0.9315424878319221for 48/51x < 50/51
f(x) = 1for 50/51x ≤ 1
f(x) = f(2-x)for 1< x ≤ 2
Illustration
α(f) < 0.3809268534330870
 maximal for 4/51 ≤ |k| ≤ 36/51 and 40/51 ≤ |k| ≤ 42/51

Discovered: May 2011

Published as e-print: September 2016