Back to Minimum overlap problem
n = 35
f(x) = 0 | for 0 | ≤ x < 6/35 | ||
f(x) = 0.03238003560575 | for 6/35 | ≤ x < 8/35 | ||
f(x) = 0.46469335227746 | for 8/35 | ≤ x < 10/35 | f(x) = 1 | for 10/35 | ≤ x < 12/35 |
f(x) = 0.08179883609036 | for 12/35 | ≤ x < 14/35 | ||
f(x) = 0.32969693439226 | for 14/35 | ≤ x < 16/35 | ||
f(x) = 0.69700395490768 | for 16/35 | ≤ x < 18/35 | ||
f(x) = 0.50267022624400 | for 18/35 | ≤ x < 20/35 | ||
f(x) = 0.72207503730147 | for 20/33 | ≤ x < 22/35 | ||
f(x) = 0.31005623320619 | for 22/35 | ≤ x < 24/35 | ||
f(x) = 0.86664405573480 | for 24/35 | ≤ x < 26/35 | ||
f(x) = 0.65866221465766 | for 26/35 | ≤ x < 28/35 | ||
f(x) = 0.84471706808832 | for 28/35 | ≤ x < 30/35 | ||
f(x) = 0.78739476150616 | for 30/35 | ≤ x < 32/35 | ||
f(x) = 0.98857595739413 | for 32/35 | ≤ x < 34/35 | ||
f(x) = 0.92726266518752 | for 34/35 | ≤ x ≤ 1 | ||
f(x) = f(2-x) | for 1 | < x ≤ 2 |
maximal for 4/35 ≤ |k| ≤ 30/35 |