Back to Minimum overlap problem

n = 11
f(x) = 0 for 0x < 2/11
f(x) = 0.40927102724537031493078911531197074319496439451091for 2/11x < 4/11
f(x) = 0.48949727431597144473464116714975062426573698805027for 4/11x < 6/11
f(x) = 0.59195016227654047852123164261388200249258432927523for 6/11x < 8/11
f(x) = 0.76613894272687659312982232136375498416154510138067for 8/11x < 10/11
f(x) = 0.98628518687048233736703150712134329177033837356584for 10/11x ≤ 1
f(x) = f(2-x)for 1< x ≤ 2
Illustration
α(f) < 0.38209359817161709135358049671482690617182364440023
 maximal for 2/11 ≤ |k| ≤ 8/11
Discovered: 1992 (refined 1993)